Description:
Mathematical discussions and pursuits.
|
|
|
God, the universe, Hawking.
|
| |
God did not create the universe, says Hawking. In my view he is wrong because what he said is 'nothing' is INFORMATION. At the beginning was IMAGINARY time. [link]
|
|
Raven's VIN psychic channel = V9T
|
| |
ON VIDEO (iPhone cable still missing) I say aloud "SHOW ME THE VIN" open to a random page, point exactly to V9. (VIN) Not much, but BETTER THAN YOU CAN DO! AND RAVEN STILL CHEATED!!!!! Herc
|
|
JSH: Some suspicions and a plan?
|
| |
One thing that has bugged me for years is the ease with which I can prove any number of things, or show remarkable happenings around my research--and have a mathematical community that remains quiet, except for on Usenet!!! Somehow, no matter what, Usenet posters will reply in the negative regardless of evidence or argument and I've long suspected that... more »
|
|
JSH: Fairly simple to prove
|
| |
I think it interesting to start a thread on the SOCIAL aspects of this result, as it was always fairly trivial in a way relying on the distributive property as those who notice my thread on broken symmetry can easily see, where I again use a VERY simple system of equations: 7(g_1(x) + 1)(g_2(x) + 2) = (f_1(x) + 7)(f_2(x) + 7) = 7*P(x)... more »
|
|
JSH: Broken symmetry and algebraic integers
   
|
| |
The ring of algebraic integers has special properties which force it to require symmetry, so breaking symmetry with it, can produce mathematical results of interest. Here is simple broken symmetry fun with which to experiment: 7(g_1(x) + 1)(g_2(x) + 2) = (f_1(x) + 7)(f_2(x) + 7) = 7*P(x) where P(x) is a quadratic polynomial with integer coefficients, and... more »
|
|
Question: small system of differential inequalities
|
| |
Hello everyone, I would appreciate if anyone could help with solving the following system. PROBLEM: Given a point x_0. The function g(x) is any 3-time differentiable, continous, square integrable function from R to R that satisfies: Condition I : abs(g(x_0)) /G_1 <= abs(g_2(x_0)) /G_3 Condition II: \int_R g^2(x) <= (4/3) abs(g(x_0))^3 / G_1... more »
|
|
|